]> Achievement Stats » Steam 游戏 » Jacob Jones and the Bigfoot Mystery : Episode 1

Jacob Jones and the Bigfoot Mystery : Episode 1

完成游戏所需平均时间:4.5 小时

21 个成就,价值 16.70 分
成就 描述 获取时间 分值 属性回报
Starting Point Starting Point Earn 10000 merits 2014-09-22 20:15:37 0.64
Survivalist Survivalist Survive the First Night in camp 2014-09-22 20:15:38 0.71
First Step First Step Complete your first puzzle 2014-09-22 20:15:39 0.59
Junior Puzzler Junior Puzzler Complete 5 puzzles 2014-09-22 20:15:39 0.66
Pale Garbage Kid Pale Garbage Kid Collect 40 soda cans 2014-09-22 20:15:40 0.68
Bird in the Hand Bird in the Hand Collect 3 Gnatgobblers 2014-09-22 20:15:40 0.74
Unjammed Unjammed Complete 'Log Jam' in less than 12 moves 2014-09-22 20:15:41 0.69
Storyteller Storyteller Complete Episode 1 2014-09-22 20:15:41 0.79
Order of Merit Order of Merit Earn 40000 merits 2014-09-22 20:15:42 0.76
Maximus Meritus Maximus Meritus Earn maximum merits for Episode 1 2014-09-22 20:15:42 1.02
Pilots Licence Pilots Licence Reach the Airfield 2014-09-22 20:15:42 0.77
Mythbuster Mythbuster Meet a Bigfoot 2014-09-22 20:15:42 0.74
Intermediate Puzzler Intermediate Puzzler Complete 10 Puzzles 2014-09-22 20:15:42 0.75
Professor Puzzle Professor Puzzle Complete 20 puzzles 2014-09-22 20:15:43 0.84
Garbage Collector Garbage Collector Collect all soda cans 2014-09-22 20:15:43 0.94
Gnats Gnobbled Gnats Gnobbled Collect all Gnatgobblers 2014-09-22 20:15:43 0.89
Circuit Trained Circuit Trained Complete 'Circuit Training' in less than 9 moves 2014-09-22 20:15:43 1.00
Digested Digested Complete 'That Ain't Sitting Right' in less than 13 moves 2014-09-22 20:15:43 0.93
Quick Picker Quick Picker Complete 'Pack Mentality' in less than 9 moves 2014-09-22 20:15:44 0.90
Low Roller Low Roller Complete 'Rolling Blunder' in less than 27 moves 2014-09-22 20:15:44 0.92
Low Notes Low Notes Complete 'A Note of Friendship' in less than 6 moves 2014-09-22 20:15:44 0.74

DLC 最后更新时间:2024-10-31 18:34

下次自动更新时间:2025-05-13 16:40

Achievement Stats 1.23-dev
已执行 4 次查询
已使用 908.22 KiB 内存
20 个获取器可用

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